Here you do have one prior distribution for e(j) - it’s a Normal(mu, sd) where mu=0 and sd=1. If you want to have one posterior for the 10 e(j)s you will need to define a hyperprior (e.g., on the mu of the Normal)
Here you do have one prior distribution for e(j) - it’s a Normal(mu, sd) where mu=0 and sd=1. If you want to have one posterior for the 10 e(j)s you will need to define a hyperprior (e.g., on the mu of the Normal)